![]() ![]() The value of metises doesn't depend on who says the same if you change to 50 to 100 point. I don't depend on en, so it doesn't matter to me. There was interest in this part of the distribution of the x bar, so we need to say what will happen with the men. The sample standard deviation will decrease if this is true. If you increase this sample size, this ratio will decrease because the end of hers is in the denominator. The sample size will increase to 100 point if it's changed now. So in this question, they are saying what will happen with this number here. Standard deviations are divided by the square root of the x bar. The first question we want to ask is if the standard deviation of the sampling distribution of the simple means is normal when we have a large sample. The sampling distribution of the sample mean has mean equal to Σ equal to 15, and a simple random sample of size 64 is taken. Mean µ equal to 100 and a known population standard deviation Suppose the random variable X has a known population If X is normally distributed with a population mean ofġ23 and a population standard deviation of 12, the samplingĭistribution of the sample mean can be assumed to be normal forĤ. There is not enough information given to answer theģ. Sample mean (or the mean of the sample means) change if the sampleĭ. How does the mean of the sampling distribution of the The sample size is increased from 50 to 500?Ģ. The standard deviation of the sample mean distribution) change if Standard error of the sampling distribution of the sample mean (or For a given population standard deviation, how does the And I'll answer this and said this option. So we'll say that option D is also wrong and as the option is option C and D is also points. So as to conclude that whether uh, X x bar will be normally distributed or not, given that the sample is not. The size and equal to 20 is a really small number. So we have given that the sample is normally distributed sample, Right? But the expert that we are taking will also include the size and equal to 20. The d option given to a source if the sample normally distributed. Right? So we can say that if the variable X in the population at all were distributed, then any sample of a size 20 will also be normally distributed out of that population. I, opponents are also normally distributed and with the same you and variants that it had. So if the variable X in the population normally distributed, we do know that summation of X. Therefore, even the option is the third option given to us is if it's variable Thanks in the population. Now, with only this limited information, we cannot conclude that excite is normally distributed or summation of X. Excite where Some 600 Division is equal to food. So let us assume an example where we know the standard division of some population variable. Normally distributed, distributor sample Yeah, option B is if the standard division of the population variable is no for the option uh in a way, option at this given if standard deviation were represented by S. The expectation will also be north equal to excited which implies act then not. So if X I are not normally distributed then summation of excite upon end. So the distribution ship of the variable, if it is, let's say an ottoman distribution. If option is regardless of the distribution shape of the variable in the population. The sampling distribution of X bar which is actually submission of all X. So we have been given a sample of size 20 and then we have to find that the sampling distribution of X bar. Is regardless of no distribution ship mm of the ready about and relation. And the question the sample size given us and it's equal to 20. ![]()
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